Math, asked by jeonjungkookbutter, 2 days ago

when 1 is added to the numerator as well as well he denominator of a certain fraction it becomes 3/5 if 1 is subtracted from both the numerator and the denominator it becomes 1/2 find the fraction​

Answers

Answered by tennetiraj86
25

Given :-

If 1 is added to both numerator and denominator of a fraction then it becomes 3/5.

If 1 is subtracted from both numerator and denominator then it becomes 1/2.

To find :-

The fraction

Solution :-

Let the numerator be X

Let the denominator be Y

The fraction = X/Y

Condition -1 :-

If 1 is added to both numerator and denominator of a fraction it becomes 3/5.

Therefore, (X+1)/(Y+1) = 3/5

On applying cross multiplication then

=> 5(X+1) = 3(Y+1)

=> 5X+5 = 3Y+3

=> 5X-3Y = 3-5

=> 5X - 3Y = -2 ---------(1)

Condition -2:-

If 1 is subtracted from both numerator and denominator of a fraction it becomes 1/2

Therefore, (X-1)/(Y-1) = 1/2

On applying cross multiplication then

=> 2(X-1) = 1(Y-1)

=> 2X-2 = Y-1

=> 2X-Y = -1+2

=> 2X-Y = 1 -------------(2)

On multiplying (2) with 3 then

6X-3Y = 3 ---------------(3)

On subtracting (1) from (3)

6X-3Y = 3

5X-3Y = -2

(-)

__________

X + 0 = 5

__________

Therefore, X = 5

On substituting the value of X in (2) then

2(5)-Y = 1

=> 10-Y = 1

=> -Y = 1-10

=> -Y = -9

=> Y = 9

The numerator = 5

The denominator = 9

The fraction = 5/9

Answer :-

The original fraction = 5/9

Check :-

The numerator = 5

The denominator = 9

The fraction = 5/9

If 1 is added to both numerator and denominator of a fraction it becomes (5+1)/(9+1) = 6/10 = 3/5

If 1 is subtracted from both the numerator and the denominator it becomes (5-1)/(9-1) = 4/8 = 1/2

Verified the given relations in the given problem.

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