when 1 is subtracted from each of the numerator and denominator of a fraction, in becomes ½ and when one is added to each of them it becomes ⅔. find the fraction
Class 8
Advance Mathematics
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Let the numerator = x
denominator = y
According to question,
x + 1 / y + 1 = 2 / 3
3x + 3 = 2y + 2
3x - 2y = -1 ----------------1
x - 1 / y - 1 = 3 / 5
5x - 5 = 3y - 3
5x - 3y =2 ------------------2
We get 2 question , Now by Elimination Method ,
3x - 2y = -1 × 5
5x - 3y = 2 × 3
15x - 10y = -5
15x - 9y = 6
- + -
__________
-y = -11
y = 11
Now put the value of in equation 1
3x - 2(11) = - 1
3x - 22 = -1
3x = 21
x = 7
So that the value of x is and y is 11.
We know numerator = x and denominator = y
Numerator / Denominator = 7 / 11
So that the fraction is 7 / 11
Step-by-step explanation:
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