Question

When 1 L of CO2

is heated with graphite, the volume of the gases collected is 1.5 L. Calculate the number of

moles of CO produced at S.T.P.

(A)
1
/11.2
(B)
28
/22.4
(C) 1
/22.4
(D)14/22.4​

Answer 1

Answer:

CO2 reacts with graphite as follows;

CO2 + C → 2CO

At STP 1 mole of a gas occupies 22.4L

So, 22.4 L of CO2 produces 22.4 x 2 = 44.8 L of CO

Therefore,

1 L of CO2 will produce 44.8/22.4 = 2 L of CO

But the volume of gases collected = 1.5 L

The ratio of moles of CO2 to CO = 1:2

Therefore, volumes of CO2 and CO in 1.5 L = 0.5 L CO2 and 1 L CO

Number of moles in 1 litre CO = 1/22.4 = 0.045 moles

Answer 2

Answer:

Explanation:

CO2 reacts with graphite as follows;

CO2 + C → 2CO

At STP 1 mole of a gas occupies 22.4L

So, 22.4 L of CO2 produces 22.4 x 2 = 44.8 L of CO

Therefore,

1 L of CO2 will produce 44.8/22.4 = 2 L of CO

But the volume of gases collected = 1.5 L

The ratio of moles of CO2 to CO = 1:2

Therefore, volumes of CO2 and CO in 1.5 L = 0.5 L CO2 and 1 L CO

Number of moles in 1 litre CO = 1/22.4 = 0.045 moles

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