Question

When 1 mole of A react with ½mole of B2 (A + ½B2 --> AB), 100 Kcal heat is liberated and when 1 mole of A reacted with 2 moles of B2 (A + 2B2 --> AB4), 200 Kcal heat is liberated. When 1 mole of A is completely reacted with excess of B2 to form AB and AB4, 140 Kcal heat is liberated. Calculated the mole of B2 used. [Write your answer as number of mole of B2 used × 10]


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Answer 1

Answer:

Explanation:

This can be done by bond energy concept

Formation enthalpy for 1 st reaction = 1/2bond energy of b2 - bond energy of ab = 100

Formation enthalpy for 2nd reaction = 2 bond energy of b2 - 4 bond energy of ab =200

Answer 2

I hope it is helpful for u