Question

When 1 mole of benzene is mixed with 1 mole of toluene (vapour pressure of benzene – 12.8 kPa, Toluene = 3.85 kPa) Pls explain your answer.

(a) The vapour will contain equal amount of benzene and toluene.

(b) Not enough information is given for prediction.

(c) The vapour will contain a higher percentage of benzene.

(d) The vapour will contain higher percentage of toluene.

Answer 1

ANSWER ☞

Option C. The vapour will contain a higher percentage of benzene.

Explanation :-

Using the formula - P = P°AXA + P°BXB

We conclude that vapour pressure of benzene is higher. Hence it is clear that the vapour contains higher amount of Benzene than Toluene.

But why ?

Why are you leaving ??

Any problem ???

I can help you

Answer 2

Answer:

Wanna talk to you....par yha nhi ho paayegi baat...umm pin use krti tumm?