Question

When 1 mole of n2 and 1 mole of h2 is enclosed in 3l vessel and the reaction is allowed to attain equilibrium,it is found that at equilibrium there is 'x' mole of h2. The number of moles oh nh3 would be?

Answer 1

Answer:

Explanation:

The reaction is

N2 + 3H2 ⇌ 2NH3

Initial moles

1 1 0

Number of moles at equilibrium

1-y 1-3y 2y

​At equilibrium the moles of H2 is x

So, 1-3y = x

1-x = 3y

y = (1-x) / 3

Concentration of NH3 at equilibrium is 2y. Put the value of y

Concentration of NH3 at equilibrium = 2(1-x) / 3.

​

Answer 2

Answer:

2(1-x)/3

I hope it helps you.....