When 1 mole of n2 and 1 mole of h2 is enclosed in 3l vessel and the reaction is allowed to attain equilibrium,it is found that at equilibrium there is 'x' mole of h2. The number of moles oh nh3 would be?
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Answered by
159
Answer:
Explanation:
The reaction is
N2 + 3H2 ⇌ 2NH3
Initial moles
1 1 0
Number of moles at equilibrium
1-y 1-3y 2y
At equilibrium the moles of H2 is x
So, 1-3y = x
1-x = 3y
y = (1-x) / 3
Concentration of NH3 at equilibrium is 2y. Put the value of y
Concentration of NH3 at equilibrium = 2(1-x) / 3.
Answered by
11
Answer:
2(1-x)/3
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