Question

when 1 mole of nitrogen and one mole of hydrogen is enclosed 3 and reaction is allowed to attend equilibrium it is found that at equilibrium the number of moles of ammonia​

Answer 1

Answer:

2 moles

1 mole of nitrogen = N2= 14×2 = 28 u

1 mole of Hydrogen = H2= 1×2 = 2 u

Reaction:- N2 + 3H2 gives 2NH3

here now N2= 14×2= 28 u

3H2= 3×1×2= 6 u

2NH3= 2×14×1×3= 84 u

Therefore, 1 mole of ammonia = NH3= 14×3= 42

In the above reaction 2NH3 is produced 2 moles

As 42×2= 84.

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