Question

when 10^8 electron are transferred from one conductor to another conductor , a potential difference of 10 V appears between the conductor . Find the capacitance of the two conductor​

Answer 1

Given:

Number of electrons $n = 10^{8}$

Potential difference $v = 10 V$

To find :

Capacitance (C) = ?

Solution :

Charge of electron $q = 1.6$ × $10^{-19}$

Capacitance of the two conductors $C = vQ$

$C = v n q$

C = $10$×$10^{8}$×$1.6$×$10^{-19}$

$C = 1.6$×$10^{-10} F$

Hence the capacitance of conductor is $1.6$×$10^{-10} F$

Answer 2

Answer:

1.6*10^-19*10^8=1.6*10^-11

capacitance=charge/voltage

1.6*10^-11/10

=1.6*10^-12