Question

When 10 cells in series to end of resistance of 59 ohm the current is found to be 0.25Ampere but when connected in parallel are joined to ends of 0.05 ohm the current is 25 Amprere. Calculate internal resistance of equivalent cell.

Answer 1

Answer:

r= 0.1

Explanation:

in series 10e÷(59+10r)=0.25.......1 equation

in parallel 10e÷(10×0.05+r)=25.....2 equation

calculate both equation ...r= 0.1

Answer 2

Answer:

Here's your answer..

Explanation:

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