when 10 g of sulphur is burnt in 10 g of oxygen 20g of sulphur dioxide is formed?find the mass of sulphur dioxide is formed on burning 20g of sulphur in 30g of oxygen?justify by stating the law behind this asnswer.
b. state a postulate of dalton,s atomic theory
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Answered by
49
Given:
Chemical reaction:
S + O2-----> SO2
32g 32g 64g
Here ratio of S:O2 masses are 1:1
In given problem :
10g of sulphur reacts with 10g of oxygen to produce 20gm of sulphur dioxide.
Masses are in ratio 1: 1
But if 20g of sulphur reacts with 30g of sulphur then SO2= ?
Here if we see sulphur is acting as limiting reagent which limits the formation of SO2.
HENCE,
20g of sulphur reacts with 20g of oxygen to produce 40gms of SO2 and 10gm of oxygen is left without reacting.
In above given problem , law of constant proportion is followed.
The postulate of Dalton's atomic theory which governs above problem is " the elements consist of atoms having fixed mass and that number and kind of atoms of each element in a given compound is fixed."
Chemical reaction:
S + O2-----> SO2
32g 32g 64g
Here ratio of S:O2 masses are 1:1
In given problem :
10g of sulphur reacts with 10g of oxygen to produce 20gm of sulphur dioxide.
Masses are in ratio 1: 1
But if 20g of sulphur reacts with 30g of sulphur then SO2= ?
Here if we see sulphur is acting as limiting reagent which limits the formation of SO2.
HENCE,
20g of sulphur reacts with 20g of oxygen to produce 40gms of SO2 and 10gm of oxygen is left without reacting.
In above given problem , law of constant proportion is followed.
The postulate of Dalton's atomic theory which governs above problem is " the elements consist of atoms having fixed mass and that number and kind of atoms of each element in a given compound is fixed."
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