Question

When 10 ml of hydrogen and 12.5ml of chlorine are allowed to react the final mixture contains under the
same condtions​

Answer 1

Answer: Let’s assume that the reaction is taking place in the STP conditions, such that 10ml of H2 and 12.5ml of Cl2 is equal to 0.45 and 0.55 millimoles of H2 and Cl2 respectively.

2HCl is the product that is obtained when H2 and Cl2 reacts.

So, it can be said that 1 mole of H2 reacts with 1 mole of Cl2 to form 2 moles of HCl.

Similarly, when 0.45 millimoles of H2 reacts with 0.45 millimoles of Cl2, 0.9 millimoles of HCl is formed. The unreacted Cl2 is 0.1 millimoles.

Therefore, the reaction mixture contains 0.10 millimoles of Cl2 and 0.9 millimoles of HCl.

At STP, this is equal to 20.16ml of HCl and 2.24ml of Cl2.

Explanation: Hope it was helpful.