Question

When 100 ml ozonised oxygen is passed through turpentine oil there was a reduction of volume by 20 ml. if 100 ml of such mixture is heated what will be the increase in volume.
10 ml
20 ml
40 ml
no change in volume

Answer 1

When 100 ml ozonised oxygen is passed through turpentine oil there was a reduction of volume by 20 ml. if 100 ml of such mixture is heated what will be the increase in volume.

10 ml

20 ml

40 ml

no change in volume

Answer 2

Explanation:

Molar mass of ozonized gas =

0.98

32

=33.65g/mol.

Let x be the mole fraction of O

2

and 1−x be the mole fraction of ozone.

∴ x(32)+(1−x)48=33.65

x=14.35/16=0.896

% of O

3

=(1−x)×100=(1−0.896)×100=10.4%