When 100g of steam is added to 0.4 kg of water at 30 degree Celsius , the resultant temperature of the mixture is
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Answer:
I AM ASSUMING THAT STEAM IS AT 100 DEGREE CELCIUS...
Explanation:
TEMPERATURE OF STEAM = 100 *C
TEMPERATURE OF WATER = 30*C
MASS OF WATER = 0.4 Kg
MASS OF STEAM = 0.1 Kg
ACCORDING TO FORMULA
m1 c1 T1 = m2 c2 T2
0.1 x 2.1 x [100*C - T] = 0.4 x 4.2 X [ 30*C + T]
100 - T = 240 + 8T
140 / 9 = T
=> 410 / 9 DEGREE CELCIUS
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