Question

When 100j of wok is done on a fly wheel, its angular velocity is increased from 60 rpm to 180 rpm. What is the moment of inertia of the wheel?

Answer 1

heya meta here is ur solution ✌️✌️


Workdone on a flywheel, W = 100J 

initial angular velocity, = 60rpm = 60 × 2π/60 = 2π rad/s 

Final angular velocity, = 180rpm = 180 × 2π/60 = 6π rad/s 

Now, workdone on a flywheel = change in rotational Kinetic energy 

100J = 1/2 I- 1/2I

200 = I[ (6π)² - (2π)² ] 

200 = I[ 36π² - 4π² ] 

I = 200/32π² = 0.633 kgm²




hope it helps u❤️❤️