Question

when 100J of work is done on a fly wheel its angular velocity is increased from 60 rpm to 180 rpm. what is moment of inertia of the wheel​

Answer 1

Answer:

According to work energy theorem,

Change in rotational kinetic energy gives us the work done.

Rotational kinetic energy is given by

KE = 1/2 I w^2,

where I is the moment of inertia, and w ia the angular velocity.

Now as per the question, the angular velocity is given in rpm. You have to convert to radian/second.

to convert rpm to radian /second multiply with 2π and divide by 60.

Therefore the

work done= 1/2 {I (w2 ^2 - w1 ^2)}

w2 is the final angular velocity, w1 is the initial angular velocity.

From this equation you have to calculate the "I".

Now refer to the attached file to understand better.

The answer is 25/{4(π^2)}

Answer 2

Answer:

Moment of inertia of the wheel is 25/4π^2 kgm^2.

Explanation:

If the angular velocity is given in rpm.

To convert into rad/s , we multiply by

2π/60.

Work done = change in kinetic energy

Work done =∆K

Wf and Wi is the final and initial angular velocity of the wheel.

I is the moment of inertia of wheel.

The measure of the property by virtue of which a body revolving about an axis opposes any change in rotational motion is known as moment of inertia.

Si unit of moment of inertia is kgm^2.