Question

When 100ml of 0.1 molar h2so4 is mixed with 500 ml of 0.1 molar naoh then nature of resulting solution and normality of excess of reactant left

Answer 1

Moles of H+ in H2SO4 = MV = 0.2 * 100 = 20 mmol
Moles of OH- in NaOH = MV = 0.1 * 500 = 50 mmol

Moles of OH- > Moles of H+
∴ Resultung solution is basic.

Normality of excess reactant = Excess equivalents / Total Volume
= (50 - 20) / (100 + 500)
= 30 / 600
= 1/20 N
= 0.05 N