When 100ml of M/10 H2So4 is mixed with 500ml of M/1 NaOH. Then nature of resulting solution and normality of excess od reactant left is..
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Normality=Molarity×n-factor
So the normality of h2so4 is This is because n factor of h2so4 is 2. similarly the normality of naoh is 1/10.
Thus the meq of h2so4 are 20 and meq of h2so4 are 50. so the resultant solution is alkaline.
Meq remaining are 30. As N×V=meq, we get the normality as 30÷600=1÷20
Hope this helps!
So the normality of h2so4 is This is because n factor of h2so4 is 2. similarly the normality of naoh is 1/10.
Thus the meq of h2so4 are 20 and meq of h2so4 are 50. so the resultant solution is alkaline.
Meq remaining are 30. As N×V=meq, we get the normality as 30÷600=1÷20
Hope this helps!
Akankshaasiingh:
Answer is basic, N/20
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