Question

When 100ml of M/10 NaOH H2SO4 is mixed with 500 ml ofM/10NaOH then nature of resulting solution and normality of excess of reactant left is

Answer 1

Gram equivalent of h2so4=normality *volume(in litre)=1/5×100/1000=0.02

Gram eq. Of Naoh=1/10×500/1000=0.05

So nature of solution will be basic as gram eq of Naoh are more..

So after use of 0.02 eq H2so4, eq left=0.05–0.02=0.03 (600 ml/0.6 lit)

So normality of excess reactant left is=gram Eq/vol(lit.)=0.03/0.6=0.05N

Answer 2

Gram equivalent of h2so4=normality *volume(in litre)=1/5×100/1000=0.02

Gram eq. Of Naoh=1/10×500/1000=0.05

So nature of solution will be basic as gram eq of Naoh are more..

So after use of 0.02 eq H2so4, eq left=0.05–0.02=0.03 (600 ml/0.6 lit)

So normality of excess reactant left is=gram Eq/vol(lit.)=0.03/0.6=0.05N