When 105 is added to one third of a number, the result is two times the original number. What is the original number?
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Let the number be x.
One third of the number = x/3.
Number added to x/3 = 105.
Twice the original number = 2x.
According to condition,
x + (x/3+105) = 2x
or, x + {(x+315)/3} = 2x
or, x + (x+315)/3 = 2x
or, (3x+x+315)/3 = 2x
or, 4x + 315 = 2x × 3
or, 4x + 315 = 6x
or, 6x = 4x + 315
or, 6x - 4x = 315
or, 2x = 315
or, x = 315/2
or, x = 157 ¹/₂
or, x = 157.5
Hence, the original number is 157.5.
Hope this helps you to get to your answer.
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