Question

When 12 ohm resistor is connected with a moving coil galvanometer then it's deflection reduces from 50 division to 10 divisions what is the resistance of galvanometer ???

Answer 1

Answer:

As S = G[Ig/(I – Ig)] ∴ G = [{(I – Ig)S}/Ig] = [(Kɸ – kɸ1)/(kɸ1)]s G = [(ɸ – ɸ1)/ɸ1]s given : ɸ = initial divisions = 50 ɸ1 = final divisions = 20 s = shunt resistance = 12Ω ∴ G = [(50 – 20)/20] × 12 G = 18ΩRead more on Sarthaks.com - https://www.sarthaks.com/348469/the-deflection-in-a-galvanometer-falls-from-50-division-to-20-when-12-shunt-is-applied

Answer 2

Explanation:

when the moving coil of galvanometer than its deflection reduces from 50 degrees into 10 division than the resistance of galvanometer of resistance is connected with a moving coil at 12 ohm.❤️‼️