When 127 g of copper reacts with 32 g of oxygen gas to form copper (II) oxide, no copper or oxygen is left over. How much copper (II) oxide is produced?
Answers
Answered by
5
Answer:
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Answered by
7
Answer:
2Cu+O
2
→2CuO
Total mass on reactants side =127g+32g=159g that should be equal to the mass of products that is 159g
The correct option is D.
Explanation:
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