Question

when 13511,13903,and 14589 are divided by greatest nmbr of n remainder in m what is value of (n+m)​

Answer 1

HEY BRAINLY USER

UR ANS IS 183

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EXPLANATION

=> ASSUME  THE FIRST NUMBER BE  N   which divides 13511, 13903 and 14589 LEAVING  A REMINDER  M .

=>THEN THE  REQUIRED NUMBER  WILL BE H.C.F  OF  13511-M, 13903-M  AND 14589-M.

=> IT MAY  ALSO BE THE   H.C.F OF

(13903-M)-(13511-M)   AND (14589-M)-(13903-M)

( CALCULATE H.C.F )

THAT IS 392 AND686.

( THEN AGAIN TAKE H.C.F OF 392 AND 686 )

=> H.C.F OF  392  AND 686 = 98

THE REQUIRED NUMBER N IS 98.

TO FIND THE REMINDER OF   M THEN , DIVIDE ANY OF THE NUMBER BY 98

Lets take 13903

139030 DIVIDED BY  98 GIVES  85  AS REMINDER

HENCE M+N = 98+85 = 183

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THANKS

HAVE A NICE DAY

Answer 2

Answer:

183

Step-by-step explanation:

If a number 'a' and a number 'b' are divisible by a number 'n' then, a+b and a-b is also divisible by n

=> let the number be n which divides 13511, 13903 and 14589 leaving a reminder m.

=> the required number then becomes H.C.F of 13511-m, 13903-m and 14589-m.

=> it could also be the H.C.F of  

(13903-m)-(13511-m) and (14589-m)-(13903-m)

i.e. 392 and 686.

=> H.C.F of 392 and 686 = 98

the required number n is 98.  

To find the remainder m , divide any of the given numbers by 98 . Lets take 13511  

13511/98 gives 85 as remainder.

Hence , m+n = 98+85 = 183