Chemistry, asked by shanilahameed5386, 5 hours ago

When 14.5 g of So2 reacts with 21 g of O2, What will be the theortical yield and percentage yield of the reaction if the actual yield is 12g?

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Answered by suthark95619
0

Answer:

Sample CalculationTheoretical yield of product=12.641 g Na2S2O3x (1 mol 12.641 g Na2S2O3 / 126 g) x (1 mol Na2S2O3-5H20/1 mol Na2S2O3) = 0.1003254 mol Na2S2O3-5H200.1003254 mol Na2S2O3.5H2O x 248 g Na2S2O3-5H2O = 24.88 gPercentage yield= (10.391 g / 24.88 g) x 100 = 41.76%Discussion The theoretical yield of Na2S2O3. ...

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