When 150 ml of 2 M NaOH was added to 100 ml of a H2SO4 solution, it required 43 ml of 0.5 M HCl to neutralize the excess base. What was the original concentration of H2SO4?
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Answered by
10
Answer:
150*2 = 100 * 2 * x + 43*0.5
=> 200x = 300-21.5
=> x = 278.5/300
=> x = 0.92molar
Explanation:
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Answered by
6
Answer:
1.39M
Explanation:
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