Question

When 150 ml of 2 M NaOH was added to 100 ml of a H2SO4 solution, it required 43 ml of 0.5 M HCl to neutralize the excess base. What was the original concentration of H2SO4?

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Answer 1

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150 * 2 = 100 * 2 * x + 43 * 0.5

= > 200x = 300-21.5

= > x = 278.5 / 300

= > x = 0.92 molar