Question

When 15g of mixture of nacl and na2co3 is heated with hcl 2.5 g of co3 is released at stp. find % of original mixture?

Answer 1

Answer:

Explanation:

   Now from above equation

   1 mole of CO2 is generated by 1 mole of Na2CO3

   And here 2.5 g of CO2 = 0.056 Mole.

   So 2.5 g of CO2 is generated via 0.056 mole of Na2CO3.

   And 0.056 mole of CO2 = 0.056× 105.98 (molar mass of Na2CO3) = 5.93g.

   So amount of Na2CO3 in 15 gm of mixture = 5.96 gm.

   Amount of NaCl in mixture = 15–5.96= 9.04 gm.

It is all about stoichiometric comparison, if you follow those these types of question can be easily calculated.