When 1800 J of energy is supplied to a mass m of liquid in a container, the temperature of the liquid and the container changes by 10 K. When the mass of the liquid is doubled to 2m, 3000 J of energy is required to change the temperature of the liquid and container by 10 K. What is the specific heat capacity of the liquid in J k g − 1 K − 1 ? A. 60 m B. 120 m C. 180 m D. 240 m
Answers
Answer:
You Can Get 2 answer
Explanation:
Formula: Q= mΔct
where Q= Energy supplied
m= mass of the substance
c= Specific heat
Δt= Change in temperature
In Case (i)
Q=1800 J
mass=m
Specific heat= ? ( we have to find it)
ΔT = 10k
According to formulae
1800=m(c)(10)
1800/10=m(c)
180=mc
180/m = c
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In Case (ii)
Q=3000 J
mass=2m
Specific heat= ? ( we have find it)
ΔT = 10k
According to formulae
3000=m(c)(20)
3000/20=m(c)
150=mc
150/m = c
But in option there answer as 180 m so the answer would be 180 m
The correct option is B) 120 m.
Here's why:
Specific heat capacity is defined as the amount of energy required to raise the temperature of 1 kg of a substance by 1 K.
- Let the specific heat capacity of the liquid be represented by the symbol "c".
- when 1800 J of energy is supplied to the liquid of mass m, the temperature of the liquid and the container changes by 10 K. Therefore, we can write:
1800 J = c * m * 10 K
Similarly, when the mass of the liquid is doubled to 2m, 3000 J of energy is required to change the temperature of the liquid and container by 10 K. Therefore, we can write:
3000 J = c * 2m * 10 K
rearrange both equations to solve for "c":
c = 180 J / (m * K)
c = 150 J / (m * K)
Since the specific heat capacity of the liquid should be constant, equate both expressions for "c":
180 J / (m * K) = 150 J / (m * K)
Solving for "m", we get:
m = 6 kg
Substituting the value of "m" into either equation for "c", we get:
c = 120 J / (kg * K)
Therefore, the correct option is B) 120 m.
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