Question

when 1lt of 1M nacl solution in water is mixed with 1lt of 1M cacl2 in water. Then what is the concentration of remaining chloride ions? ​

Answer 1

Explanation: please make me brainlist

50 ml of 0.1 M NaCl we have 0.005 moles of chloride ions.

In 50ml of 0.1 M BaCl

2

we have 0.01 moles of chloride ions

So, total moles of chloride ions =0.01+0.005=0.015

Total volume of solution =100ml

So, molarity of chloride ion =

100

0.015

×1000=0.15M

Hence, the correct option is C.