When 2^256 is divided by 17 then find the remainder. The first and correct answer will be MARKED AS BRAINLIEST!!!!
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Powers (Remainders)
1 (2)
2 (4)
3 (8)
4 (16)
5 (32–17=15)
6 (15*2–17=13)
7 (13*2–17=9)
8 (9*2–17=1)
9 (1*2=2)
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So the cyclic pattern here is: 2, 4, 8, 16, 15, 13, 9, 1 and repeat. So, 2^8= 256 when divided by 17 leaves out a remainder of 1.
Now, 2^(256)= 2^(8*32)
=(2^8)^32
=256^32
Since remainder of 256 is 1. And powers of 256/17 is always one. So, the answer is 1.
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=6.81129935E+75 is your answer.
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