Math, asked by Umachandru238, 1 year ago

When 2^256 is divided by 17 then find the remainder. The first and correct answer will be MARKED AS BRAINLIEST!!!!


gdfvirx: 15
Umachandru238: Sorry the answer should be -1
Umachandru238: The answer is plus 1

Answers

Answered by HimaniVarshney
8

Powers (Remainders)

1 (2)

2 (4)

3 (8)

4 (16)

5 (32–17=15)

6 (15*2–17=13)

7 (13*2–17=9)

8 (9*2–17=1)

9 (1*2=2)

.

.

.

So the cyclic pattern here is: 2, 4, 8, 16, 15, 13, 9, 1 and repeat. So, 2^8= 256 when divided by 17 leaves out a remainder of 1.

Now, 2^(256)= 2^(8*32)

=(2^8)^32

=256^32

Since remainder of 256 is 1. And powers of 256/17 is always one. So, the answer is 1.

Thankss.

hope it helps you

please mark the answer as Brainliest.


HimaniVarshney: Thanks for selecting as Brainliest
Umachandru238: Ur welcome
josh73: hii
josh73: good answer
HimaniVarshney: Thanks
josh73: which state u r
Answered by Rhits
2

=6.81129935E+75 is your answer.

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