Question

when 2 balls of mass 4kg and2 kg are moving with speed 10m/s and 8 m/s collide thenThe common velocity of the system of balls during collision will be?​

Answer 1

Answer:

Provided that:

• Mass of ball A = 4 kg
• Mass of ball B = 2 kg
• Speed of ball A = 10 mps
• Speed of ball B = 8 mps

To determine: The combined velocity of system after collision.

Solution: The combined velocity of system after collision = 9.33 mps

Using concept: The conservation of law of momentum formula.

Using formula:

${\small{\underline{\boxed{\sf{\rightarrow \: m_A u_A + m_B u_B \: = m_A v_A + m_B v_B}}}}}$

(Where, ${\sf{m_A}}$ denotes mass of object one, ${\sf{u_A}}$ denotes initial velocity of object one, ${\sf{m_B}}$ denotes mass of object two, ${\sf{u_B}}$ denotes initial velocity of object two, ${\sf{v_A}}$ denotes final velocity of object one, ${\sf{v_B}}$ denotes final velocity of object two.)

Required solution:

$:\implies \sf m_A u_A + m_B u_B \: = m_A v_A + m_B v_B \\ \\ :\implies \sf 4(10) + 2(8) = (4+2)v \\ \\ :\implies \sf 40 + 16 = 6v \\ \\ :\implies \sf 56 = 6v \\ \\ :\implies \sf 56/6 = v \\ \\ :\implies \sf 28/3 = v \\ \\ :\implies \sf 9.33 \: = v \\ \\ :\implies \sf v \: = 9.33 \: ms^{-1}$