When 2-bromobutane reacts with alcoholic KOH,
the reaction is called
(a) halogenation
(b) chlorination
(c) hydrogenation
(d) dehydro halogenation
Answers
Answered by
12
Answer:
d is correct ..........
Answered by
0
(d) dehydro halogenation
Explanation:
The reaction between 2-bromobutane and KOH results in the removal of halogen as well as the hydrogen from substrate and produces KBr and water as products of the reaction. This reaction is called dehydro halogenation reaction.
Option D is the answer.
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