Question

When 2 coulomb charge flows through a conducter in 2 second , the current flowing in the conductor is

Answer 1

Solution :

1 Ampere current flowing in the conductor .

Step by step Explanatíon :

We have ,

Charge ,Q =2 C

Time , t = 2 sec

We have to find the current flowing in the conductor

We know that :

Current $\sf\:I=\dfrac{dq}{dt}$

Put the given values

$\sf\:I=\dfrac{2C}{2sec}$

$\sf\:I=1Cs^{-1}$

$\sf\green{I=1A}$

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More About the topic :

Electric Current

The time rate of flow of charge through any cross section is called electric current.

• Electric Current = Q/t
• It is measured in Ampere (A)
• If n electrons pass through a point in a conductor in time t then the current through the conductor is , I = ne/t
• Two types of current : a) Direct current and b) Alternative current

Answer 2

$\large \bf { \underline{\underline{ \red{ \: \: Con} \color{orange}{cept} \red : - }}}$

$\sf\small{Here, \: in \: this \: concept \: we \: have \: to \: find \: the \: current \: flowing \: } \\ \sf\small { in \: the \: conductor \:or \: Electric \: Current \: which \: is \: represented \: } \\ \sf\small {as \: I \: ,by \: the \: formula \: given \: below. \: Here \: the \: Electric \: charge (Q)}\: \\ \sf\small{ is \: given \: and \: Time \: taken \: is \: given \: in \: the \: query.}$

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$\large \bf { \underline{\underline{ \pink{ \: \: Gi} \color{deeppink}{ven} \pink : - }}}$

$\small\begin{gathered}\frak{} \begin{cases} & \sf{Electric \: Charge, \: (Q) \leadsto \: \boxed{ \bf \color{navy}{ 2 \: Charge \: \: }}} \\ & \sf{} \\ & \sf{ Time \: taken \: ,( \: t \: )\leadsto \boxed{ \bf {\green{2 \: Seconds}}} } \end{cases}\\ \\\end{gathered}$

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$\large \bf { \underline{\underline{ \blue{ \: \: To \: } \color{navy}{find} \blue : - }}}$

• $\small\bf \:{Electric \: Current,(I)} \leadsto \boxed{ \bold ?}$

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$\large \bf { \underline{\underline{ \pink{ \: \: For} \color{purple}{mula} \red : - }}}$

$\pink \bigstar \bf \boxed { \bf \large {I}= \large \frac{Q}{ \large t} } \purple\bigstar$

$\small \sf{Where,} \: \\ \\ \small \sf \boxed {\bf I } \red\longrightarrow Electric \: current \\ \small \sf \boxed{ \bf Q} \green\longrightarrow Electric \: charge \: \\ \small \sf \boxed{ \bf t} \red\longrightarrow \: Time \: taken \: \: \: \: \: \: \:$

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$\large \bf { \underline{\underline{ \pink{ \: \: Sol} \color{orange}{uti} \green{on} \red : - }}}$

$\sf{By , applying \: the \: formula} \: \leadsto \: \pink \bigstar \bf \boxed { \bf \large {I}= \large \frac{Q}{ \large t} } \purple\bigstar \\ \\ \sf Putting \: the \: values, \\ \\ \large \tt\blue➦ I = \frac {\cancel{2 }\: charge} {\cancel{2} \: seconds} \\ \\ \large \tt\blue➦ I= 1 \: Cs {}^{ - 1} \\ \\ \large \tt\blue➦ I \: = 1 \: Ampere$

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$\large \bf { \underline{\underline{ \green{ \: \: Expl} \color{deepgreen}{ore} \: \pink{More} \red : - }}}$

• $\bf \: \leadsto Unit \longrightarrow\: Amperes (A) \:$
• $\bf \: \leadsto \pink{ Defination}\longrightarrow\: \\ \\ \bf An \: electric \: current \: is \: a \: flow \: of \\ \bf particles \: (electrons) \: flowing \: through \\ \bf wires \: and \: components. \\ \bf \purple{ It \: is \: the \: rate \: of \: flow \: of \: charge.} \:$

• $\bf \: \leadsto Current \longrightarrow\: Rate \: of \: flow \: of \: charge\:.$

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$\large \bf { \underline{\underline{More \pink{ \: \: For} \color{purple}{mulas} \red : - }}}$

$\purple \bigstar \bf{Voltage,(V)}= \large \frac{E}{Q} \green \bigstar$

$\purple \bigstar \bf{Resistance,(R)}= \large \frac{V}{I} \green \bigstar \:$

$\purple \bigstar \bf{Power,(P)}= V \times I \green \bigstar \:$

$\purple \bigstar \bf{Conductivity \: ,(σ )}= \large \frac{1}{P} \green \bigstar \:$

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