when 2 force a and b are mutually at right angle their resultant is 20 KN when they are enclined at 60 the resultant is 6√5 KN individual magnitude of forces
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Let the forces be F1 and F2
F1^2 + F2^2 = 10
as the angle between them is 90 degrees
when angle is 60
F1^2 + F2^2 + 2 * F1 * F2 *cos(60)=13
10 + F1 * F2=13
3 = F1 * F2
(F1 + F2)^2 = F1^2 + F2^2 + 2 * F1 * F2 = 10 + 6 = 16
F1 + F2 = 4...............(1)
F1 - F2 = √( ( F1 + F2)^2 - 4F1 * F2) = 2.......(2)
from eq.(1) and (2) We get
F1 = 3N ,and F2 = 1 N
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