When 2 grams of fuel is completely burnt in excess of oxygen, the temperature of a calorimeter of thermal capacity 100 cal gram containing 2900 grams of water rises by 3°C. Find the calorific value.
(A) 3500 cal/g (C) 3900 cal/g (B) 4000 cal/g (D) 4500 cal/g 1
Answers
The calorific value of the fuel is equal to 4500 cal/g. The correct option is (D) 4500 cal/g.
Given:
The mass of fuel used = 2 grams
The thermal capacity of the calorimeter = 100 cal °C⁻¹
The increase in the temperature of the water = 3°C
The mass of the water = 2900 grams
To Find:
→ The specific heat capacity of a substance is the amount of heat energy required to raise the temperature of 1 gram of a substance by 1°C. If the mass of the body is 'm' and the specific heat capacity is 'c', the amount of heat supplied is 'Q' and the temperature change is ΔT then:
→ The heat capacity of a substance is the amount of heat energy required to raise the temperature of the given substance by 1°C. If the heat capacity of the body is 's', the amount of heat supplied is 'Q' and the change in temperature is ΔT then:
The thermal capacity of the calorimeter (s) = 100 cal °C⁻¹
The specific heat capacity of water (c) = 1 cal g⁻¹ °C⁻¹
The increase in the temperature of the water (ΔT) = 3°C
→ Let the total heat energy required for the process be 'Q'.
Since the amount of heat energy required for the process is 9000 Calorie, therefore the heat energy released by the fuel is equal to 9000 Calorie.
→ The calorific value of a substance is the amount of heat released by the complete combustion of the unit mass of that substance. The S.I. unit of calorific value is J/kg.
∵ The mass of the fuel (m) is 2 grams and the amount of heat released (Q) is equal to 9000 calorie.
∴ The calorific value of the fuel will be given as:
The calorific value of the fuel comes out to be equal to 4500 cal/g. Hence the correct option is (D) 4500 cal/g.
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