Question

when 2 numbers are separately divided by 33, then the remainder are 21 and 28 respectively, if the sum of the 2 numbers is divided by 33, then the remainder is ?​

Answer 1

Answer:

smallest such numbers which when divided by 21 and 28 leaves the given remainder of 21 and 28 could be for the value of a=0 and b=0, i.e 21 and 28. So, irrespective the value of 'a' and 'b' , 33(a+b) will always be divisible by 33. So we are left with 49 now.