When 20 g of naphthoic acid is dissolved in 50g of benzene (Kf=1.72K kgmo 1^−1), a freezing point depression of 2 K is observed. The van't Hoff factor (i) is:
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Answered by
1
Explanation:
Correct option is
A
0.5
Molaloity =
172×50
20×1000
=2.32
∴ Depression in freezing point =2=2.32×1.72×i
∴i=0.5
Answered by
3
Answer:
Molaloity =
172×50
20×1000
=2.32
∴ Depression in freezing point =2=2.32×1.72×i
∴i=0. 5
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