Question

when 20 ml of water is added to 80 ml of 5 M NaCl solution what is the molarity of resulting solution ​

Answer 1

Answer:

20 molar

Explanation:

M1V1=M2V2

given M1=5M

V1=80 ml

V2=20 ml

M2=400/20

= 20 molar

Answer 2

The molarity of the resulting solution is 4 M

Explanation:

According to the dilution law:

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock NaCl solution = 5 M

$V_1$ = volume of stock NaCl solution = 80 ml

$M_2$ = molarity of diluted NaCl  solution = ?

$V_2$ = volume of diluted NaCl solution =(80+20) ml = 100 ml

Putting in the values, we get:

$5M\times 80=M_2\times 100$

$M_2=4M$

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