When 200 is divided by a positive integer x, the remainder is 8. How many values of x are there?
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Given :
200 is divided by a positive integer x.
The remainder is :
=8
To Find :
Values of x = ?
Solution :
∴200 is divisible by x , so according to Euclidean Algorithm :
200 = qx + r ;
where q is quotient and r is remainder obtained on dividing 200 by x.
So , 200 = xq + 8 -(1)
∴The remainder is always less than the divisior , so :
x > 8 .
Now from eq 1 we have ;
xq = 200 -8
xq = 192
Now from the prime factorisation of 192 :
So , we see that 192 is divisible by 2, 3, 4 , 6 , 8 , 12 , 14 , 16 , 24 , 32, 64 and 192
But we want x > 8
So the values of x are 12 , 14 , 16 , 24 . 32 , 64 and 192.
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