Question

When 200N force is applied on an object, its length increases by 1 mm. So potential energy stored in it due to this change is ............ .
(A) 0.2 J
(B) 10 J
(C) 20 J
(D) 0.1 J

Answer 1

Answer:

c.20.j is answer for me which I got

Answer 2

Answer:

So potential energy stored=0.2J

So option (A) is correct.

Explanation:

since we know that as per the work-energy theorem, work done is equals to the energy.

W.D.=Energy stored (work energy theorem)

we know the formula for W.D.

work done = force x displacement

Here force is given which is 200N

And dispalcement=1 mm

So, $W.D.=200\times10^{-3}$

W.D.=0.2J

This work done is stored in the form of energy so,

So, potential energy stored=0.2J