When 20cm³ of a gaseous hydrocarbos were completely burnt in an excess of oxygen, 60 cm³ of carbon dioxide and 40cm³ of water vapour were formed , all volumes being measured at the same temperature and pressure. What is the formula of hydrocarbons?
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The said hydrocarbon with a general chemical formula of CxHy completely burns in an environment with excess of oxygen O2 according to this combustion reaction:
CxHy + (x+y/4) O2 → x CO2 +y/2 H2O
So, based on the given information, one can write:
x = 60/20 = 3
y/2 = 40/20 = 2
giving
y = 4
Then, this results in C3H4 as the hydrocarbon in the problem, which from organic chemistry can be one of the below compounds:
Propadiene: H2C=C=CH2
Propyne: CH3—C≡CH
Cyclopropene (with a triangular structure including one double bond).
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