When 22.4 liters of H2 is mixed with 11.2 liters of Cl2 each at 273k at 1 atm. The moles of Hcl formed is equal to
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1 mole of any gas at STP occupies 22.4 liters of volume
22.4 liters of H2 indicates 1 mole
11.2 liters of Cl2 indicates 0.5 moles
H2 + CI2 --------------------> 2HCI
initially - 1 0.5 0
equilibrium 1 - 0.5 0.5 - 0.5 2(0.5)
0.5 0 1
Therefore 1 mole of HCl is formed finally with 0.5 moles of H2 left unreacted.
22.4 liters of H2 indicates 1 mole
11.2 liters of Cl2 indicates 0.5 moles
H2 + CI2 --------------------> 2HCI
initially - 1 0.5 0
equilibrium 1 - 0.5 0.5 - 0.5 2(0.5)
0.5 0 1
Therefore 1 mole of HCl is formed finally with 0.5 moles of H2 left unreacted.
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