when 22.4 liters of hydrogen is mixed with 11.2 liter of chlorine, each STP,The moles of hcl formed is equal to
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H2 + 2Cl=2HCl
2 mol +2mol=2mol
but 1/2 mol of cl is available
Cl. HCl
2 = 2
0.5. = x
x=2*0.5/2=1/2=0.5 mol of HCl will be formed
2 mol +2mol=2mol
but 1/2 mol of cl is available
Cl. HCl
2 = 2
0.5. = x
x=2*0.5/2=1/2=0.5 mol of HCl will be formed
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