Question

When 22.4 litre of h2 is mixed with 11.2 litre of cl2 at stp the moles of hcl formed is equal to?

Answer 1

Answer:

H2 + CL2-> 2HCL

22.4 L 22.4 L 2×22.4

22.4 Litres hydrogen reacts with 22.4 litre of chlorine to give 44.8 L of HCL

the given volume of chlorine is 11.2 L 

here chlorine is the liming reagents as its . first consumed 

22.4 Litre of chlorine gives 73 litre of HCL 

so , 11.2 l gives 44.8/22.4 × 11.2 = 22.4 of HCL is formed 

that means no. of mole = 1 

because 1 mole of any gases occupies 22.4 L at STP

Explanation: