Question

When 22.4 litres of H,(g) is mixed with 11.2 litres of
Cl(g), each at S.T.P, the moles of HCl(g) formed is
equal to
a) 1 mol of HCl(g) (b) 2 mol of HCl(g)
(e) 0.5 mol of HCl(g) (d) 1.5 mol of HCI(g)
(AIPMT 2014)​

Answer 1

d is the answer

Explanation:

no of mole of H=22.4/22.4=1. no of mole of Cl=11.2/22.4=0.5. no of mole of HCL =33.6/22.4=1.5.