Question

When 22.4 Litres Of H2 (G) Is Mixed With 11.2 Liters Of Cl2 (G), Each At Stp, The Moles Of Hcl(G) Formed Is Equal To(A) 1 Mol Of Hcl (G)(B) 2 Mol Of Hcl (G)(C).0.5 Mol Of Hcl(G)(D) 1.5 Mol Of Hcl (G)

Answer 1

When 22.4 Litres Of H2 (G) Is Mixed With 11.2 Liters Of Cl2 (G), Each At Stp, The Moles Of Hcl(G) Formed Is Equal To

$\huge\bold{Answer}$

22.4 L of Cl2 produces 2×22.4 L of HCl

Which means ,

1 mole of Cl2 produces 2 moles of HCl

So 0.5 mole{11.2 L} will produce 1 mole of HCl

Hence $\bold{Option\:A}$ is correct i.e. 1Mol of HCl

Answer 2

$<marquee direction="up" >⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆</marquee >$

Answer

When 22.4 Litres Of H2 (G) Is Mixed With 11.2 Liters Of Cl2 (G), Each At Stp, The Moles Of Hcl(G) Formed Is Equal To(A) 1 Mol Of Hcl (G)✔✔✔(B) 2 Mol Of Hcl (G)(C).0.5 Mol Of Hcl(G)(D) 1.5 Mol Of Hcl (G)