When 22.4 litres of H2(g) is mixed with 11.2 litres
of Cl (9), each at STP, the moles of HCl(g) formed
is equal to
[AIPMT 2014]
(I/ 1 mol of HCl(g) (2) 2 mol of HCl(g)
(3) 0.5 mol of HCl(g) (4) 1.5 mol of HCl(g)
Answers
Answered by
2
Answer:
3)0.5 mil of HCl
Explanation:
i hope it helps you friend
Answered by
2
Answer
3)0.5 mil of HCl it's correct Answer
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