when 22.4 litres of h2 (g)is mixed with the 11.2 litres of Cl2(g),each at STP, the moles of HCL(g)formed is equal to
Answers
Answered by
2
Answer:
Cl2=0.5mole here the limiting reagent is cl2 so
1mole of cl2 gives 2moles of hcl then 0.5 moles cl2 gives how many moles of hcl
2×0.5÷1 =1mole
Similar questions