when 22.4litre of h2 gas is mixed with 11.2 litre if cl2 gas at stp the moles of hcl gas
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1 mole of hydrogen require 1 mole of cl
So 22.4 liter of cl2 require 22.4 of h2
1 liter of cl require 22.4 ÷ 22.4 of h2
And
11.2 liter of cl require 22.4 ÷ 22.4× 11.2 of h2
= 1× 11.2 = 11.2 liter of hydrogen
1 mole = 22.4 liter so
0.5 mole = 11.2 liter
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