Question

.When 2240 J of heat is supplied to a metal piece of mass 450g, its temperature

rises from 25oC to 65oC. Then find-

i) heat capacity of metal piece​

Answer 1

Answer:

Given: m=50g;△t=327

∘

C−27

∘

C=300

∘

C,Q=2400 J

Now, Q=mc△t

2400=50×C×300

Specific heat capacity of the metal, c=

50×300

2400

=0.16 J/g

∘

C