Question

When 229 J of energy is supplied as heat at constant pressure to 3mol Ar(g),the temperature of the sample is increased by 2.55K. Calculate molar heat capacity at constant volume.

Answer 1

Hey there !

Since the given number of moles is larger than 1 we take the formula

• Cp - Cv = nR

Here,

1. Cp = Constant Pressure
2. Cv = Constant value
3. n = Number of moles
4. R = Real gas constant

We know that,

Cp = q / Δ T ( T = Temperature )

=> Cp = 229 / 2.55 = 89.8 J / K

Cv = Cp - nR

=> Cv = 89.8 J / k - ( 3 × 8.314 )

=> Cv = 89.8 - 24.94

=> Cv = 64.85

Cv per mole = 64.85 / 3 = 21.61 J / k . mol

Hope my answer helped !